The straight line
cuts the
-axis at
and
-axis at
. A circle is drawn through and the origin. The sum of the perpendicular distances from
on to the tangent drawn at origin to the circle S is
Text Solution
Verified by ExpertsB
Given line
intercepts the axes at
and
.
So,
and
Let centre
be (h, k).
According to question.
For 

……………… ..(i)
For :

For origin
…………… ..(iii)
For (i)
{using (iii) }
from (ii)

Put value of in equation (
.

Satisfy point 

Here centre
Equation of tangent is 

Put 

Perpendicular distance from
Perpendicular distance from 
Sum of distance from
and 

So, option is correct.
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